Correct answer: Qd81...K:c3[a] 2.Rb3#[A] 1...K:e3/[б]/ 2.Rg3#[Б] 1.Qh7[C]? zz 1...K:c3[a] 2.Rb3#[A] 1...K:e3/[б]/ 2.Rg3#[Б] 1...d:c3[d] 2.Kf4#[D] but 1...d:
