Correct answer: Bd21...N:c4[a] 2.B:c6#[A]/Nd6#[Б] 1...Q:f5/[б]//Q:c4[c] 2.B:c6#[A] 1...Bg3/Bd2 2.N:g3# 1...Qd6 2.N:d6#[Б] 1.R:e6? (2.B:c6#[A]/N