Correct answer: Qb51...Bc7/Ba7 2.B:c7# 1...Q:f3 2.B:f3# 1...Qf5/Qf6/Qf7/Qf8/Qg3/Qh2/Q:g5 2.Bc4#/Bb3#/Ba2#/Bc6#/B:b7# 1.