Correct answer: Ng51...c2 2.Bb2# 1...Be6 2.Bd6# 1.Nf2? (2.Nd3#[C]/Qd6#[Б]) 1...Rd7[a] 2.Nf:g4# 1...Bd7/[б]/ 2.Nd3#[C] 1...Bf5 2.Qd6#[Б] but 1.
