Correct answer: Qd41...Bd4[a]/Bc3/Bb2/Ba1 2.Be4#[A] 1...B:d3 2.B:d3# 1...B:f4 2.Q:f4# 1...e:d5 2.Rf5# 1...R:f7+ 2.B:f7# 1.B:e5? (2.Bf5#[Б]/
