Correct answer: Kc51...Ne3[a] 2.d3#[A] 1...B:e2/[б]/ 2.Re3#[Б] 1...Nh4/Ne1 2.R:g4# 1.Kd7[C]? zz 1...Ne3[a] 2.d3#[A] 1...B:e2/[б]/ 2.Re3#[Б] 1...Nh4/<