Correct answer: Nd21...c6/c5[a] 2.Qd6# 1...R:c3 2.Nd:c3#/Ne:c3# 1...B:e3+ 2.N:e3# 1.Ne:f2? (2.e4#[A]) 1...e4[c] 2.Q:e4#[Б] 1...R:c3 2.N:c3# but 1...d6/[б]/!
