Correct answer: B:b21...Nf3[a]/Rc3+[d] 2.Kc3#[A] 1...Be3/[б]//Rg2/Rg1 2.Kc3#[A]/Kd3#[Б] 1...Rd3[c] 2.K:d3#[Б] 1...R:g6/Rf5/R:e5 2.Qf5# 1...Q<