Correct answer: N:d51...Nd2[a]/Nd6[a]/Nb2[a]/Na3[a]/Na5[a] 2.Q:d5#[A] 1...B:f4/[б]//Bf6/[б]//Bg7/[б]//Bh8/[б]//Bd6/[б]//Bc7/[б]//Bb8/[б]/ 2.R:d5#[Б]
