Correct answer: Nf51...d2[a] 2.Bc2#[A] 1...Ng3/[б]//Nh2[c]/Nf:e3/[б]//Nd2[c] 2.N:g3#[Б] 1...g3[d] 2.Bf3#[C] 1...e:d4[e] 2.Re6#[E] 1...Nd:e3/Ne7/Nf4/N:f6/N<