Correct answer: Qf51...Kd6[a] 2.Qd4#[A] 1...Ne4/[б]//Ne6[c] 2.Q:e5#[C] 1...Ngf7 2.Qd2#[Б] 1...Nef3/Nef7/Ng4/Ng6/Nd3/Nd7/Nc4 2.Bc4# 1.<
