Correct answer: f31...Be4[a]/Rf3[a] 2.R:e4#[Б] 1...Bf3/Ne3/[б]//Rh4/R:h5[d]/Bg3 2.d4#[A] 1...d5[c] 2.Nc6#[D] 1...Rg3[e]/Bg1 2.f4#[C] 1...Ng3 2.f4#[C]/d4#[A]
