Correct answer: Na51...Nd4[a] 2.Rc5#[A] 1...Q:c3/[б]//Qf2/Qc5/Qb6/Qa7 2.Q:e4#[Б] 1...Q:f4+[c] 2.N:f4#[C] 1...Ng5 2.Qf5# 1.R:e3? (2.Q:e4#[Б]/<