Correct answer: Ba21...Kd4 2.Qf4#[A] 1...c6/c5 2.Qd6# 1...f6 2.Qe3# 1.Nd8? (2.Nc6#[Б]/Qf4#[A]) 1...f6 2.Qf4#[A] 1...f5 2.Nc6#[Б] but 1...Kd4! 1.Na5
