Correct answer: Nb61...Nb2[a]/Bd2/Be3/Bf4/Bh6/Ba3/[б]/ 2.Qa3#[A] 1...Bc2[c] 2.Rb6#[Б] 1...Bb3 2.Qa5# 1...B:c6+ 2.N:c6# 1.Nb6! (2.Q