Correct answer: Qc21...Kb1[a]/Nc4/[б]/ 2.Rd1#[A] 1...Nd3[c] 2.Ra4#[Б] 1...Nd1/Na4 2.R:d1#[A]/Ra4#[Б] 1.Rd5? zz 1...Kb1[a]/Nc4/[б]//Na4 2.R