Correct answer: Nd51...f:g2[a] 2.Qg4#[A] 1...d:c2/[б]/ 2.Qa6#[Б]/Qc4# 1.Q:e5? zz 1...f:g2[a] 2.Qh5#[D] 1...d:c2/[б]/ 2.Qb5#[C] but 1...e6! 1.Qa6[Б]? (2.Q:d3#) but 1...f
