Correct answer: B:g61...Ba2[a] 2.Qa1#[A] 1...e2/[б]//f2[c] 2.Q:d2#[Б] 1...B:c2 2.Q:c2# 1...Nc7+ 2.R:c7# 1...d3 2.R:d3# 1.Nc1? zz 1...Ba2[a] 2.N:a2#[D]
