Correct answer: Ba61...Qf5[a] 2.Qc6#[A] 1...Bd5/[б]/ 2.Qg6#[Б] 1...Qg2/Qg4 2.Bg4# 1...Bc2/Bd1/Bc4/Ba4 2.Bc4# 1.Qf3? (2.Qf7#[C]) 1...Q