Correct answer: R:f51...Rf2/Rf1/Rf4/Re3[a] 2.Qd5#[A]/Qc6#[Б] 1...R:c3 2.Qc6#[Б] 1...f4 2.Re5# 1.Q:f3? (2.Qd5#[A]/Qc6#[Б]) 1...Bb3 2.Qc6#[Б
