Correct answer: Nc51...e6+[a] 2.Bg7# 1.Nd8? zz 1...e6+[a] 2.Ndf7#[Б] 1...Kd6/[б]//Nb6/Na7 2.Q:c7#[A] 1...Nd6 2.Bg7# 1...Ng2/Ng6/Nh3/Nh