Correct answer: Qc41...Nb5[a] 2.Rd1#[A]/Qa2#[Б] 1.Rd3[C]? (2.B:f6#/Q:f6#) 1...Nb5[a] 2.Rd1#[A] 1...Nc6/[б]/ 2.Qa2#[Б] 1...R:g8 2.B:f6# but 1...<
