Correct answer: e:d51...Ne6[a] 2.Nf7#[Б] 1...Rc3/Rb3/Ra3 2.d4#[A] 1...Nd7/Na4 2.Bc7#[C] 1.B:b6? (2.Bc7#[C]) 1...Ne6[a] 2.Nf7#[Б] but 1...a:b6!
