Correct answer: Bd31...Bg4 2.Nf4#[A] 1.g8Q? (2.Nf4#[A]/Qh4#[Б]) 1...Kh6/[б]/ 2.Qgh8#/Nf4#[A] but 1...Kg4[a]! 1.g8R? (2.Qh4#[Б]/Nf4#[A]) 1...K