Correct answer: Re41...Bf4/Bg3[a]/Bh2[a]/Bb8[a] 2.Nb4#[A] 1...Be7/Bf8/[б]//Bc5/Ba3/[б]/ 2.Nc7#[C] 1...Be5 2.Nb4#[A]/Ne7#[Б] 1...Bb4/Bc7 2.<
