Correct answer: Qd31...Kf4[a] 2.Q:d6#[A] 1...d5/[б]/ 2.Bb8#[Б] 1...Ng6[c]/Ng8[c]/Nd5[d]/Nc6[c]/Nc8[c] 2.N:g6#[C] 1...c3[e] 2.Nd3#[D] 1...Nf4/Ng1/Ng3/