Correct answer: Rf51...f:e6[a] 2.R:f8#[A] 1...B:g7 2.Nh:g7# 1...Rg8 2.R:g8# 1.Rg8? (2.R:f8#[A]) 1...B:f6+/[б]/ 2.N:f6#[Б] 1...Bg7 2.Nh:g7# but 1...R<