Correct answer: Rg11...Bg4[a] 2.Qd2#[A] 1...Bg6/[б]//Bf7[c]/Be8[d] 2.R:f3#[Б] 1...Bg1/Bg3 2.Qg3# 1.Ke6? zz 1...Bg4[a] 2.Qd2#[A] 1...Bg6/[б]/
