Correct answer: Qh11...Qb6[a]/Qc6[a]/Qd6/[б]//Qe6[a]/Qf6[a]/Qh6[a]/b5[a] 2.Qe2#[Б] 1...Qb5[c]/Qc4[c]/Qf1[c]/b6[c] 2.Qg6#[A] 1...Kd3 2.Q:f3# 1...Qa
