Correct answer: Qc71...Ke4[a]/Nd7/[б]//Ne6/[б]//Nb3/[б]//Nb7/[б]//Na4/[б]//Na6/[б]/ 2.Bf5#[A] 1...Kc4/Ne4[c] 2.Be2#[Б] 1.Bf6? zz 1...Ke4[a] 2.B<