Correct answer: Be11...Kf8[a]/Kd6/[б]//Nf6[c]/Ng7[d]/Nc7[c] 2.Bb4#[A] 1...Nd6[e] 2.Bf6#[Б] 1.Bd4? zz 1...Kf8[a]/Nf6[c]/Ng7[d]/Nc7[c] 2.Bc5#[
