Correct answer: B:c51...Qf6[a]/Qg7/[б]//Qh8[c]/Qb2/Qa1[d] 2.R:c5#[A] 1...Qc7[e] 2.R:e4#[C] 1...Qe6/Qe8 2.R:c5#[A]/Qd4#[Б] 1...Qe7/Qf5/Q:f4/