Correct answer: Nd31...Nf3+[a] 2.g:f3#[A] 1...Ng5/[б]//Nf2[c]/Nf4[d] 2.Qf4#[Б] 1...d5[e] 2.Bb1#[C] 1.c4? (2.Bb1#[C]) 1...Nf3+[a] 2.g:f3#[A] 1...Nf2[c]/Nf4[d] 2.<