Correct answer: Bc81...Kc4[a] 2.Be6#[A] 1...Ke4 2.Qf3# 1.Qh5+? 1...Kc4[a] 2.Qb5#[C] 1...Kd6/[б]//Kc6[c] 2.Qc5#[Б] but 1...Ke4! 1.Qh7? zz
