Correct answer: Ne11...Nf2[a] 2.Q:f2#[A] 1...Bg5/[б]//Bf6[c] 2.Rh3#[Б] 1...Ne4[d]/Nf1[d]/N:f3[d]/Nc4[d]/Nb1[d]/Nb3[d] 2.Bf4#[C] 1.B:d2? (2.Bf4#
