Correct answer: Qc71...e4[a] 2.Bf4#[A] 1.Qc8? zz 1...e4[a] 2.Bf4#[A] 1...f4/[б]/ 2.Qg4#[Б] 1...Be7[c]/Bd6[d]/Bc5[e]/Bb4[e]/Ba3[e] 2.Qg8#[C] but 1...Bg7
