Correct answer: Qc51...Re5[a]/Re4[a]/Re3[a]/Re2[a]/Re1[a]/Re8/[б]//Rd7[c] 2.Qd7#[A] 1...Rc7[d] 2.Qe8#[Б] 1.Nd5? zz 1...Re5[a]/Re4[a]/Re3[a]/