Correct answer: Qa51...Kf3 2.Ng5# 1.Qe2? zz 1...Kd5[a] 2.Qc4#[Б] 1...f5/[б]/ 2.Bc6#[C] but 1...Kf5! 1.Nd6+?? 1...Kf3 2.Be2#/Qe2#/Qd1#/R<