Correct answer: Qg71...R:e5[a]/d:c5/d:e5 2.Nc1#[A] 1.Qb6? (2.Qb4#) 1...R:e5[a] 2.Nc1#[A] 1...R:c5/[б]/ 2.R:d6#[Б] but 1...d:c5! 1.Qf7?? (2.Qf4#/Qf2#)