Correct answer: Qg21...c4[a] 2.Qd4#[A]/Bc6#[Б] 1...Bc4 2.Bc6#[Б] 1...Nb4/Nc3 2.Nc3# 1.Nd2[C]? (2.Bc6#[Б]) 1...c4[a] 2.Qd4#[A] 1...B:b5/[б]/ 2.Rh5#[