Correct answer: N:f41...Ng7/Nf6[a] 2.Q:f4# 1...Bb2 2.Q:b2# 1...f3 2.Qe3# 1.Rd1? (2.Nd7#[A]) 1...Nf6[a] 2.Q:f4# but 1...Bd4/[б]/! 1.R:h6? (2.N<