Correct answer: Kc81...B:c5[a] 2.Nc7#[A] 1...d:c5/[б]//d5 2.c7#[Б] 1...Bc3/Bd2/Be1 2.N:c3# 1...Ba3 2.N:a3# 1.c7[Б]? (2.c8N#) but 1...B:c5[a]! 1.Nc7[A]? (2.
