Correct answer: B:f71...Ng2/Ng6/Nf3/Nf5 2.Nf5# 1.Qd6? zz 1...c:d3[a]/c3/[б]/ 2.Ra4#[A] 1...e:d3[a] 2.Bg1#[Б] 1...Ng2/Ng6/Nf3/Nf5 2.Nf5#
