Correct answer: Qc11...Kd5[a] 2.Qh1#[A] 1.Be5[Б]? (2.Q:d6#) but 1...Kc7/[б]/! 1.Bf6[C]? zz 1...Kd5[a] 2.Qh1#[A] 1...Kc7/[б]/ 2.Qc1#[D] but 1...d5[c]! 1
