Correct answer: Na51...Ng4[a]/Ng8/N6f5/Nf7 2.Bf7#[A] 1...Ng2/Ng6/[б]//Nf3/N4f5 2.Bf3#[Б] 1...Bc6 2.Qe5# 1...Bd4 2.R:d4# 1...Be3 2.Q