Correct answer: Be51...Rc6[a] 2.Q:c4#[A] 1...Ne5/Nf6/Nf8/N:c5/Nb6/Nb8 2.R:e5# 1...c:d3 2.R:d3# 1.f5? (2.Rd4#[Б]) 1...K:e4 2.Q:c4#[A] but 1...