Correct answer: Rd71...c5 2.a8Q#/a8B# 1...c3 2.Ba2# 1...Be5 2.Be4# 1.Nf7[Б]? (2.Be4#) 1...Re5/e5/B:e1/[б]/ 2.Nc7#[C] 1...c3 2.Ba2# but 1...Bf2[a]
