Correct answer: Qb51...Ne3[a]/Nf2[a]/Nb2[a] 2.N:e3#[A] 1...g6/[б]//g5/[б]/ 2.Ngf6#[Б] 1...Nc6[c] 2.Qe6#[C] 1...Nd7[d]/N:a6[e] 2.Q:a8#[D] 1.Qc8? zz 1...N