Correct answer: Ne51...d6[a]/d5[a] 2.Ne6#[A] 1...c5/[б]/ 2.Bb2#[Б] 1...e3[c] 2.Rd1#[C] 1...N:g4/Ng8/Nh5/Nh7/Ne8/Nd5 2.R:e4# 1.Ne7? zz 1...d6[a]/d5[a] 2.N<