Correct answer: Nd41.Nb4[A]? (2.Nc6#) 1...f4[a] 2.Qd5#[Б] 1...Rf4/[б]/ 2.Qe8#[C] but 1...Kf4! 1.Rd4? (2.Qe8#[C]/Qd5#[Б]) 1...f4[a] 2.Qd5#[Б]/Rd5#
